Wood Density in weight per cubic dimension
determine the weight of a cubic unit of wood given secific gravity & moisture content.
$$\rho_x = \rho_w G_x \left( 1 + x / 100 \right)$$
where $\rho_x$ is the wood densityn the same units as the water density, $\rho_w$ is the water density in the units of interest, $G_x$ is the specific gravity at a specified moisture content, and $x$ is the desired output moisture content.
The equation from Wood Handbook Chapter 4, page 10-12, General Technical Report FPL-GTR 190.
"Specific gravity $G_x$ is defined as the ratio of the density of a substance to the density of water $\rho_w$ at a specified reference temperature, typically 4° C (39° F), where $\rho_w$ is 1.000 g cm-3 (1,000 kg m-3 or 62.43 lb ft-3)." (Wood Handbook)
Example
- Imperial Units
- sg or $\rho_x$ = 0.4
- mc or $x$ = 12.0
- wdensity of $\rho_w$ = 62.43 cf ft-3 or 1000 kg m-3
- Answer = 27.968 lb. ft-3 or 448 kg m-3
Code
This code is stored in my Github.com\larsendr site. These are direct links to the raw code.
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